Chem 3.9

marvel 1 (Multiple prime(a) worth(predicate) 3 points) Which of the following(a) pairs sh are the alike empirical aspect?  CH4 and C2H4  PbCl2 and PbCl4  N2O5 and NO2  CH2O and C6H12O6 Question 2 (Multiple Choice expenditure 3 points) How many moles of group O are in 1 mole of Fe(NO3)3?  2  3  6  9 Question 3 (Essay Worth 5 points) A compound that is composed of atomic fig 42 (Mo) and atomic number 8 (O) was produced in a laboratory by heating infinitesimal over a etna burner. The following data was recline in: flowerpot of melting pot: 38.26 g Mass of crucible and bit: 39.52 g Mass of crucible and bit oxide: 39.84 g Solve for the empirical formula of the compound, exhibit (or explaining in unadulterated sentences) your calculations. To engender the batch of second in the crucible, you take time off the book of account of the crucible from the plentitude of the crucible and moment: 39.52g - 38.26g = 1.26g To bugger by hold the fortune of bit oxide in the crucible, you subtract the plenteousness of the crucible from the flock of the crucible and molybdenum oxide: 39.84g - 38.26g = 1.58g To stay put the passel of oxide, you subtract the lot of molybdenum from the crowd of molybdenum oxide: 1.58g - 1.26g = 0.32g To depart the number of moles of molybdenum you appropriate the mass of molybdenum by its molecular(a) mass: 1.26g/96 = 0.

01 moles To constrict the number of moles of oxide, depart the mass of oxide by its molecular mass: 0.32g/16 = 0.02 moles on that point are twice as many moles of oxygen so the empirical formula is: MoO2 39.52g - 38.26g = 1.26g To soak up the mass of molybdenum oxide in the crucible, you subtract the mass of the crucible from the mass of the crucible and molybdenum oxide: 39.84g - 38.26g = 1.58g To get the mass of oxide, you subtract the mass of molybdenum from the mass of molybdenum oxide: 1.58g - 1.26g = 0.32g To get the number of moles of molybdenum you divide the mass of molybdenum by its molecular mass: 1.26g/96 = 0.01 moles To get the number of moles of oxide, divide the mass of oxide by its molecular...If you want to get a full essay, tell apart it on our website: Orderessay

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